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17.5-2.54x-0.48x^2=0
a = -0.48; b = -2.54; c = +17.5;
Δ = b2-4ac
Δ = -2.542-4·(-0.48)·17.5
Δ = 40.0516
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2.54)-\sqrt{40.0516}}{2*-0.48}=\frac{2.54-\sqrt{40.0516}}{-0.96} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2.54)+\sqrt{40.0516}}{2*-0.48}=\frac{2.54+\sqrt{40.0516}}{-0.96} $
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